Is it possible to check for more than one error in one except line?

What does the following code do: @something def some_function(): pass

Output of the following script? def f(a, L=[]): L.append(a) return L print(f(1)) print(f(2)) print(f(3))

What method is usually used to return unicode representation of an object?

def fn(a, *b, **c): print(c) fn(5) What will be the output?

What will typing the following at the Python interpreter produce? lang = list('Python') ; lang[:-4]

Output of the following Python code? a = 1 def f(): print (a+2) def g(): a = 2 print (a+1) def h(): global a a = 3 print (a+3) print (a+4) f() print (a+2) g() print (a+1) h() print (a+2)

Output of the following Python code from the given options. set1 = set() set2 = set() for i in range(2, 6): set1.add(i) for i in range(4, 7): set2.add(i) print('Set1 = ', set1) print('Set2 = ', set2) set3 = set1 | set2 set4 = set1 & set2 print(set4) if set3 > set4: print('0') elif set3 < set4: print('2') else : print('1') if set4 < set3: print('0') set5 = set3 - set4 print(set5) if set4.isdisjoint(set5): print('1') set5.clear() print(set5)

Upon creation of the 'dumbdbm' database, files with which of the given extensions are created?

Output of the following Python code? value = [2, 3, 4, 5, 6] cd = 0 try: cd = value[3] except IndexError: print('0', end = '') except: print('1', end = '') finally: print('0', end = '') cd = 10 try: cd = cd/0 except ZeroDivisionError: print('1', end = '') finally: print('0')

Output of the following Python code. def req(str): p=2 str = str.split() str2 = [] for i in str: if i not in str2: str2.append(i) for i in range(0, len(str2)): p=str.count(str2[i])+p print(p) def main(): str =str ='apple mango apple orange orange apple guava mango mango' req(str) if __name__=='__main__': main()'>