Choose the correct output of the following Python code from the given options.

set1 = set()

set2 = set()

for i in range(2, 6):

set1.add(i)

for i in range(4, 7):

set2.add(i)

print("Set1 = ", set1)

print("Set2 = ", set2)

set3 = set1 | set2

set4 = set1 & set2

print(set4)

if set3 > set4:

print("0")

elif set3 < set4:

print("2")

else :

print("1")

if set4 < set3:

print("0")

set5 = set3 - set4

print(set5)

if set4.isdisjoint(set5):

print("1")

set5.clear()

print(set5)

Output of the following Python code? a = 1 def f(): print (a+2) def g(): a = 2 print (a+1) def h(): global a a = 3 print (a+3) print (a+4) f() print (a+2) g() print (a+1) h() print (a+2)

Correct answer from the options given below. tp1 = (Python ) m = 5 for i in range(int(m-1)):

Output of the following Python code? import math a = 3.4536 print ('Result = ',end='') print (math.trunc(a)+math.ceil(a)+math.floor(a))

Correct answer from the given options. class ErrorInCode(Exception): def __init__(self, data): self.data = data def __str__(self): return repr(self.data) try: raise ErrorInCode(1000) except ErrorInCode as ae: print ('0'ae.data) finally: print ('1')

Output of the following Python code? class Error(Exception): ''0...' pass class ValueTooSmallError(Error): '.'1uu' pass class ValueTooLargeError(Error): m2'... pass number = 10 while True: try: i_num =10 if i_num < number: raise ValueTooSmallError elif i_num > number: raise ValueTooLargeError break except ValueTooSmallError: print('1') printi) except ValueTooLargeError: print('1') printi) print('0')

What does the following code do: @something def some_function(): pass

Is it possible to check for more than one error in one except line?

filter(function, iterable) is equivalent to:

Given str='code', what will be the result of the expression str[0] = 'm'?

In order to display a value in the interactive interpreter, Python uses what method of a class?