Which of the following shell expressions in Python 3.4 will give an error?

Output of the following Python code : class Ba(object): pass class De(Ba): pass print(issubclass(De. Ba)) print(issubclass(Ba, De)) d = 090 b = 880 print(isinstance(b, De)) print(isinstanceld. 88))

Output of the following Python code? class Ba(object): def _init_(se|f, x): self‌ix = x+2 class De(Ba): def _init_(self. x. y): Bax = x‘2 self.y = y+2 def printXY(self): print(Ba.x+2, self.y‘2) d = De(10’2, 20+2) d.printXYO

Output of the following Python code? lis1 =[2. 1. 3, 5] lisZ = [6, 4, 3] lis1.extend[lis2) print (end=') for i in range(0, len(lis1)): print(end=' ') lisl.clear() print (end=') for i in range(2. len(lis1)): print(lisl[i]+1. end=' ')

Choose the correct output of the given Python code.

Output of the following Python code class Son: def __init_(self. n): self‌in = n print(self.n) def sayh(self): print(self.n) p = Son('0') p-sayho

What will be the value of the element a[0] after executing this set of commands? a=[1,2,3] b=a b[0]=11

what would be an answer of the code below: a = len('aa') switch a: case 1: print 2 break case 2: print 1 break default: print 0

What is the basic difference between theses two operations in 're' module: match() and search()?

Which of these list declarations will result in error?

You need to run two applications which have conflicting dependencies. What Python tool would you use to solve this problem?