What is " __doc__" for in Python?

consider next code import asyncio @asyncio.coroutine def foo1(): yield from asyncio.sleep(3.0) print('1') @asyncio.coroutine def foo2(): yield from asyncio.sleep(1.0) print('2') @asyncio.coroutine def foo3(): print('3') @asyncio.coroutine def test(): asyncio.async(foo1()) asyncio.async(foo2()) asyncio.async(foo3()) yield from asyncio.sleep(2.0) loop.stop() loop = asyncio.get_event_loop() asyncio.async(test()) loop.run_forever() loop.close() What will be printed first?

How would you write the following with a list comprehension? x = [] for i in range(5): x.append([]) for j in range(10): x[-1].append(j)

class Foo(object): def bar(self, x): pass foo = Foo() is foo.bar and foo.bar.__func__ is the same object?

If a='holy', b='grail', and c=None, what does the following expression return? a or b or c

The code 'lambda x: return x' will do what?

Output of the following Python code? x = 5.2 x **= 3 print(x)

This question is based on the graphic shown below. Choose the correct output of the given Python code.

Consider the Python 3.4.2 code that is given in the image. Choose the correct line(s) number from the following options that will not give an output as 'None'.

This question is based on the graphic shown below. The Python code given in Figure 1 of the image was supposed to give the output that is given in Figure 2, but lines number 14 and 24 are coded incorrectly. Choose the correct lines from the following options that will replace both the lines to obtain the desired output.

In relation to the exceptions in Python, which of the given exceptions is raised when a generated error code does not fall into any category?