Correct Answer: undefined
Explanation:
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Result of the following expression: var a = 'test'; console.log(!!a);
The loop isn't working. What's the problem? var foos = ['a', 'b', 'c' , 'd', 'e']; var bars = ['x', 'y', 'z']; for (var i = 0; i < foos.length; i++) { var foo = foos[i]; for (var i = 0; i < bars.length; i++) { var bar = bars[i]; /* some code using `bar` */ } }
var foos = ['a', 'b', 'c' , 'd', 'e']; var bars = ['x', 'y', 'z']; for (var i = 0; i < foos.length; i++) { var foo = foos[i]; for (var i = 0; i < bars.length; i++) { var bar = bars[i]; /* some code using `bar` */ } }
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Value of x? function foo(y) { var z = 10; z = 7; }; var x = foo('bar');
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