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By default, views are cached to improve performance. When a view is navigated away from, its element is left in the DOM, and its scope is disconnected from the $watch cycle. When navigating to a view that is already cached, its scope is then reconnected, and the existing element that was left in the DOM becomes the active view?

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By default, views are cached to improve performance. When a view is navigated away from, its element is left in the DOM, and its scope is disconnected from the $watch cycle. When navigating to a view that is already cached, its scope is then reconnected, and the existing element that was left in the DOM becomes the active view?

Answer

Correct Answer: Caching

Explanation:

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