What is the size of each header block for systems having two-byte memory pointers and available memory less than 64 bytes?

4. xyz(i,j,k);

5. return 0;

6.}

7.abc (int a, int b, int c)

8.{ for(;a<=5;a++)

9. { for(b=5;b>a;b--)

10.    { printf(" "); }

11.    for(c=1;c<=a;c++)

12.    { printf("* "); }

13.    print("\n");

14. } }

15.xyz(int *a, int *b, int *c)

16.{ for(a=4;a>=1,a--)

17. { for(b=4;b>=a;b--)

18.    { printf(" "); }

19.    for(c=a;c>=1;c++)

20.    { printf("* "); }

21.    printf("\n");

22. } }

a. 4

b. 9

c. 13

d. 14

e. 15

f. 16

g. 17

h. 19

Given the array:

int num[3][4]= {

                {3,6,9,12},

                {15,25,30,35},

                {66,77,88,99}

                };

what would be the output of *(*(num+1)+1)+1?

This question is based upon the figure shown below

The given program, which was supposed to give output as shown in the image, has some errors. Analyse the code and choose the correct line number(s) containing error(s).

1.int main( )

2.{ int i=1,j=1,k=1;

3. abc(i,j,k);

4. xyz(i,j,k);

5. return 0;

6.}

7.abc (int a, int b, int c)

8.{ for(;a<=5;a++)

9. { for(b=5;b>a;b--)

10.    { printf(" "); }

11.    for(c=1;c<=a;c++)

12.    { printf("* "); }

13.    print("\n");

14. } }

15.xyz(int *a, int *b, int *c)

16.{ for(a=4;a>=1,a--)

17. { for(b=4;b>=a;b--)

18.    { printf(" "); }

19.    for(c=a;c>=1;c++)

20.    { printf("* "); }

21.    printf("\n");

22. } }

a. 4

b. 9

c. 13

d. 14

e. 15

f. 16

g. 17

h. 19

Given the array:

int num[3][4]= {

                {3,6,9,12},

                {15,25,30,35},

                {66,77,88,99}

                };

what would be the output of *(*(num+1)+1)+1?

amessage++;

2.char *pmessage = "abcde";

(*pmessage)++;

3.char amessage[] = "lmnop";

(*amessage)++;

4.char *pmessage = "abcde";

pmessage++;

Which of the following statements is/are valid and correct?

1.char amessage[] = "lmnop";

amessage++;

2.char *pmessage = "abcde";

(*pmessage)++;

3.char amessage[] = "lmnop";

(*amessage)++;

4.char *pmessage = "abcde";

pmessage++;