Assuming integer is 4 bytes long and the address for 'i' is 2000, what is the output for the following code? int main() { int ***foo, **bar, *foobar, i=5; foobar = &i; bar = &foobar; foo = &bar; printf("%d, %d, %d\n", *foobar, **bar, ***foo); return 0; }
Correct Answer: 5, 5, 5
Explanation:
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