How is Math.Pow() implemented in the .NET Framework?
Answer
Correct Answer: Math.Pow operates on type doubles. Doubles are 64-bit floating point and have about 15-16 digits of precision in C#. Func<long, int, long> power = null; power = (i, p) => p == 1 ? i : i*power(i, p - 1); Console.WriteLine(power(15, 14));
Explanation:
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