Correct Answer: Cout object
Explanation:
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Output of the following code? #include using namespace std; class b { int i; public: void vfoo() { cout <<'In Base '; } }; class d : public b { int j; public: void vfoo() { cout<<'In Derived '; } }; void main() { b *p, ob; d ob2; p = &ob; p->vfoo(); p = &ob2; p->vfoo(); ob2.vfoo(); }
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