A new partition /dev/hda6 has been created. How will it be formatted with ext3 file system (one block=1024 bytes, inode size=one inode every 2 blocks)?

mke2fs  -b 2048 -i 2048 -j /dev/hda6

mke2fs  -b 1024 -i 1024 -j /dev/hda6

mke2fs  -b 1024 -i 2048 -j /dev/hda6

mke2fs  -b 2048 -i 4096 -j /dev/hda6

Answer:
mke2fs  -b 1024 -i 2048 -j /dev/hda6

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