If you are given two dates in this form   ??: Start Date: 2007-03-24 End Date: 2009-06-26 Which code snippet finds the difference between these two in the following form: 2 years, 3 months and 2 days PHP > 5.3

$date1 = new DateTime("2007-03-24"); $date2 = new DateTime("2009-06-26"); $interval = $date1->diff($date2); echo "difference " . $interval->y . " years, " . $interval->m." months, ".$interval->d." days ";

$date1 = new DateTime("2007-03-24"); $date2 = new DateTime("2009-06-26"); $interval = $date2->diff($date1); echo "difference " . $interval->days . " days ";

$date1 = "2008-11-01 22:45:00"; $date2 = "2009-12-04 13:44:01"; $diff = abs(strtotime($date2) - strtotime($date1)); $years = floor($diff / (365*60*60*24)); $months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24)); $days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24)); $hours = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24)/ (60*60)); $minuts = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60)/ 60); $seconds = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24 - $days*60*60*24 - $hours*60*60 - $minuts*60)); printf("%d years, %d months, %d days, %d hours, %d minuts\n, %d seconds\n", $years, $months, $days, $hours, $minuts, $seconds);

Use CodeIgniter timespan() function