In relation to watchdog timer registers, the WDTPW (watchdog timer password) is always read as which of the following options?

int i;

printf("output: ");

for (i = 0; i < num; i++)

{

    if (c[num2[i]] == 1)

    printf(" %d ", num2[i]+5);

    else

    c[num2[i]]++;

}

}

int main()

{

int num1[] = {15, 10, 10, 2, 7, 4, 2};

int af = sizeof(num1) / sizeof(num1[0]);

abc(num1, af);

getchar();

return 0;

}

Find the output of the following program and choose the correct answer from the given options.

#include <stdio.h>

#include <malloc.h>

void abc(int num2[], int num)

{

int *c = (int *)calloc(sizeof(int), (num – 2));

int i;

printf("output: ");

for (i = 0; i < num; i++)

{

    if (c[num2[i]] == 1)

    printf(" %d ", num2[i]+5);

    else

    c[num2[i]]++;

}

}

int main()

{

int num1[] = {15, 10, 10, 2, 7, 4, 2};

int af = sizeof(num1) / sizeof(num1[0]);

abc(num1, af);

getchar();

return 0;

}

abc(x);

xyz(x,y);

printa(y);

}

abc(m)

int m[][3];

{

int i, j;

for(i=0;i<3;i++)

{for (j=0; j<3;j++)

    {m[i][j]=((i+2) + (j+3));

    }}

}

xyz(x,y)

int x[][3], y[][3];

{

int i, j;

for(i=0;i<3;i++)

for (j=0;j<3;j++)

{

    y[j][i]=x[i][j];

}

}

printa(m)

int m[][3];

{

int i,j;

for(i=0;i<3;i++)

{

    for (j=0; j<3;j++)

    printf("%d ", m[i][j]);

    printf("\n");

}

}

This question is based upon the figure shown below

Choose from the given image, the correct output of the following code.

#include<stdio.h>

main ()

{

int x[3][3], y[3][3];

abc(x);

xyz(x,y);

printa(y);

}

abc(m)

int m[][3];

{

int i, j;

for(i=0;i<3;i++)

{for (j=0; j<3;j++)

    {m[i][j]=((i+2) + (j+3));

    }}

}

xyz(x,y)

int x[][3], y[][3];

{

int i, j;

for(i=0;i<3;i++)

for (j=0;j<3;j++)

{

    y[j][i]=x[i][j];

}

}

printa(m)

int m[][3];

{

int i,j;

for(i=0;i<3;i++)

{

    for (j=0; j<3;j++)

    printf("%d ", m[i][j]);

    printf("\n");

}

}